Exam Overview
It is not always possible to accurately diagnose a
fungal nail infection based on appearance alone. A
potassium hydroxide (KOH) preparation test can help determine whether you have
a fungal nail infection.
Your health professional will collect a sample of skin and/or nail
fragments (debris) under the infected nail. If a sample of debris cannot be
removed, he or she can take a nail sample by lightly scraping the nail near the
infected area or by using a small blade to shave off a piece of nail.
Nail or debris samples are placed on a slide with a potassium
hydroxide (KOH) solution and gently heated. The solution slowly dissolves the
skin and nail cells, leaving the fungus cells. The fungus cells can then be
seen with a microscope. Color stains can be used to make the fungi easier to
see.
Why It Is Done
If you have discolored, damaged, broken, or thickened nails or have
a buildup of skin and nail fragments (debris) under a nail, a KOH test can help
confirm whether a fungal nail infection is present.
Results
Normal
No fungi are present in the debris or nail sample. However, the
test may be done again using more samples taken from other parts of the
infected nail. This is because there may no longer be fungi on the edge of the
infected area, where it is easiest to scrape for a sample, or in the dead
tissue, even if you have a fungal nail infection.
Abnormal
Fungi are present in the debris or nail sample.
What To Think About
About 50% of all nail diseases are fungal nail infections.1 Because of this and the
risks associated with oral antifungal medication, your
health professional will probably confirm that you have a fungal infection
using a KOH preparation test if you are considering taking antifungal pills
(oral treatment). Many insurance companies now require testing to verify a
fungal infection before paying for medications.
If your test is normal, your health professional may do other tests
to determine the cause of the nail damage.
Complete the
medical test information form (PDF)
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to help you prepare for this test.